Transcribed Image Text: (1) A course repeater claims that his brother who did some Calculus at college years ago, but

currently on some cough medication, believes that the first derivative of

(2×2 – 1)(x² + 3)

f(x)

2х 1[(2х? – 1)(х? + 3)

2x

+

x2 + 3

4x

is f'(x) =

x2 +1

[2x² – 1

x2 + 1

x2 + 1

and

(x2 + 8)7

3x²)5]

Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you

(x² + 8)7

14x

30x

that the first derivative of g(x)

is g'(x) =

(2 – 3×2)5

[x² + 8 ‘ 2 – 3x²]

(2

confirm whether his brother is right, wrong or a little tipsy.

28

(2) In the following triangle below, the degree measures of the three interior angles and two

of the exterior angles are represented with variables and expressions.

(a) Find the size of each of the interior angle.

2x – 5

2x + 5